If the diode is sized properly I would say the bulb will not be energized without wind. But I imagine that what is drawn is not the entire circuit otherwise what does the battery power and what type battery charger is being used with the wind generator?
1 - more power goes to battery than to load(bulb)
2 - same to battery and load
3 - more power to load than battery
what is the dependent on? when will which situation occur?
Again the circuit is not complete so I could be hard to provide you with an answer but if I was a gambling man and the diode was sized and wired properly I would expect that more power would go to the battery then the load.
Actually all of the power would go to the battery and none to the load.
nice, thank you. so next - what will be the distribution formula. what will decide, if the kanthal load / battery charging will be distributed 50/50 or 10/90 or 80/20....?
i know, that battery 20% SOC will have bigger draw, then the same battery at 90% SOC. right? is there something that can be measured or counted to get the result, which is the mentioned distribution ratio?
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