The Expandable Solar Power System (Plug and Play)

[inetdog]

Are you saying that the notion of (183 Ah / 20 hours = 9.15 Ah) is wrong?
But then how else do we determine the number of Ah that a battery can give out at a desired percentage?

You are being careless again. Ah/h = A not Ah.

If you have a battery which can deliver 183 amp-hours over a 20 hour period and you discharge it so that it will be totally drained at the end of 20 hours you will end up pulling 9.15A the whole time. But that would kill the battery, so do not do that!


And as far as not answering your questions is concerned:
If your question is phrased in a way that does not make sense, the first step is to try to figure out what your real question is. Only then will it be possible to answer the question. And if you have not got your terminology straight you will not understand those answers!

Communication requires some common ground first as a reference.

[foo1bar]

You are being careless again. Ah/h = A not Ah.

If you have a battery which can deliver 183 amp-hours over a 20 hour period and you discharge it so that it will be totally drained at the end of 20 hours you will end up pulling 20A the whole time. .

inetdog meant 9.15A

I know that's what he meant because he's being clear with his units.
And therefore it is easy for me to see the mathematical mistake/typo he made.

[inetdog]

inetdog meant 9.15A

I know that's what he meant because he's being clear with his units.
And therefore it is easy for me to see the mathematical mistake/typo he made.

Fixed it, thanks.

[Maitland Gill]

inetdog meant 9.15A

I know that's what he meant because he's being clear with his units.
And therefore it is easy for me to see the mathematical mistake/typo he made.

I realized that I made some critical mistakes and that I needed 8 Batteries instead of 6. Thank you for your assistance.
Have a look at it now,

PS
Just to be sure, am I to assume the following is correct?

183 A / 20 hours = A discharge rate of 9.15 Ah | 109.8 Wh

5% of 183 A / 9.15 Ah = 1 hour

10% of 183 A / 9.15 Ah = 2 hours

20% of 183 A / 9.15 Ah = 4 hours

40% of 183 A / 9.15 Ah = 8 hours

Is this not how we determine the number of Watt-hours that a certain percent of a Battery (Given it's rate of discharge) has in it's capacity?

Or is the 9.15 Ah subject to change?

[Sunking]

I realized that I made some critical mistakes and that I needed 8 Batteries instead of 6. Thank you for your assistance.
Have a look at it now,
PS
Just to be sure, am I to assume the following is correct?

183 A / 20 hours = A discharge rate of 9.15 Ah | 109.8 Wh

Hell no that is not right. How many times must you be told not to use AH?

[inetdog]

Closed by Moderators. This thread was not going anywhere.