I am helping with the design of a Ground Mount PV system.
My friend bought a whole pallet of 275 Watt PV Panels = Qty 30.
From the PV Label ...
Voc = 38.7 volts
Isc = 9.17 amps
Vmp = 31.7 volts
Imp = 8.69 amps
And he bought an SMA 5000 watt US 240 Volt AC Grid Tie Inverter with 3 independent MPPT channels
Each channel has a 480 Volt max for MPPT, and 600 volt absolute max.
So, the first calculation we did was this ...
480 volts / 38.7 volts Voc = 12 Panels max in the Southern facing array!
Next, we calculated this ...
East Array = 9 panels x 275 Watts = 2,475 watts x 80% = 1,980 watts (net)
South Array = 12 panels x 275 Watts = 3,330 watts x 80% = 2,640 watts (net)
West Array = 9 panels x 275 Watts = 2,475 watts x 80% = 1,980 watts (net)
Total Watts of all 30 Panels = 1,980 + 2,640 + 1,980 = 6,600 Watts which is greater than 5,000 watts
So, the question is ...
"How do we calculate the ANGLE for the East & West array 'wings' with respect to the larger South Array"
We realize that for every 15 degrees, the East Array will peak 1 hour earlier and
the West array will peak 1 hour later.
Rotate the East and West arrays back 15 degrees ( 1 hour ), then at Solar Noon ...
East Array = sin(75) x 1,980 = 1,912
South Array = 2,640 watts
West Array = sin(75) x 1,980 watts = 1,912
Total watts is too high 6,464 = 1,912 + 2,640 + 1,912
Rotate the East and West arrays back 30 degrees ( 2 hours ), then at Solar Noon ...
East Array = sin(60) x 1,980 = 1,714
South Array = 2,640 watts
West Array = sin(60) x 1,980 watts = 1,714
Total watts is too high 6,068 = 1,714 + 2,640 + 1,714
Rotate the East and West arrays back 45 Degrees ( 3 hours ), then at Solar Noon ...
East Array = sin(45) x 1,980 = 1,400
South Array = 2,640 watts
West Array = sin(45) x 1,980 watts = 1,400
Total watts (input) is "OK" at 5,440 = 1,400 + 2,640 + 1,400
I am not sure we should rotate the East & West Arrays back much more, since the morning and evening sun is lower at 9am & 3pm
At 9:00AM total watts is ...
East Array = sin(90) x 1,980 = 1,980
South Array = sin(45) x 2,640 = 1,866
West Array = sin(0) x 1,980 watts = 0
Total watts from 9:00AM is 3,846 = 1,980 + 1,866 + 0
At 3:00PM total watts is ...
East Array = sin(0) x 1,980 watts = 0
South Array = sin(45) x 2,640 = 1,866
West Array = sin(90) x 1,980 = 1,980
Total watts from 9:00AM is 3,846 = 0 + 1,866 + 1,980
So, from 9:00am until 3:00pm ...
6 Hours x 4,500 Watts (avg) = 27 kWhr every sunny summer day?
Is there a better way to use all 30 PV Panels with this SMA 5kW Inverter?
My friend bought a whole pallet of 275 Watt PV Panels = Qty 30.
From the PV Label ...
Voc = 38.7 volts
Isc = 9.17 amps
Vmp = 31.7 volts
Imp = 8.69 amps
And he bought an SMA 5000 watt US 240 Volt AC Grid Tie Inverter with 3 independent MPPT channels
Each channel has a 480 Volt max for MPPT, and 600 volt absolute max.
So, the first calculation we did was this ...
480 volts / 38.7 volts Voc = 12 Panels max in the Southern facing array!
Next, we calculated this ...
East Array = 9 panels x 275 Watts = 2,475 watts x 80% = 1,980 watts (net)
South Array = 12 panels x 275 Watts = 3,330 watts x 80% = 2,640 watts (net)
West Array = 9 panels x 275 Watts = 2,475 watts x 80% = 1,980 watts (net)
Total Watts of all 30 Panels = 1,980 + 2,640 + 1,980 = 6,600 Watts which is greater than 5,000 watts
So, the question is ...
"How do we calculate the ANGLE for the East & West array 'wings' with respect to the larger South Array"
We realize that for every 15 degrees, the East Array will peak 1 hour earlier and
the West array will peak 1 hour later.
Rotate the East and West arrays back 15 degrees ( 1 hour ), then at Solar Noon ...
East Array = sin(75) x 1,980 = 1,912
South Array = 2,640 watts
West Array = sin(75) x 1,980 watts = 1,912
Total watts is too high 6,464 = 1,912 + 2,640 + 1,912
Rotate the East and West arrays back 30 degrees ( 2 hours ), then at Solar Noon ...
East Array = sin(60) x 1,980 = 1,714
South Array = 2,640 watts
West Array = sin(60) x 1,980 watts = 1,714
Total watts is too high 6,068 = 1,714 + 2,640 + 1,714
Rotate the East and West arrays back 45 Degrees ( 3 hours ), then at Solar Noon ...
East Array = sin(45) x 1,980 = 1,400
South Array = 2,640 watts
West Array = sin(45) x 1,980 watts = 1,400
Total watts (input) is "OK" at 5,440 = 1,400 + 2,640 + 1,400
I am not sure we should rotate the East & West Arrays back much more, since the morning and evening sun is lower at 9am & 3pm
At 9:00AM total watts is ...
East Array = sin(90) x 1,980 = 1,980
South Array = sin(45) x 2,640 = 1,866
West Array = sin(0) x 1,980 watts = 0
Total watts from 9:00AM is 3,846 = 1,980 + 1,866 + 0
At 3:00PM total watts is ...
East Array = sin(0) x 1,980 watts = 0
South Array = sin(45) x 2,640 = 1,866
West Array = sin(90) x 1,980 = 1,980
Total watts from 9:00AM is 3,846 = 0 + 1,866 + 1,980
So, from 9:00am until 3:00pm ...
6 Hours x 4,500 Watts (avg) = 27 kWhr every sunny summer day?
Is there a better way to use all 30 PV Panels with this SMA 5kW Inverter?
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